Q1.The perimeter of a square is 20 cm.A rectangle has the same width as the square.The length of the rectangle is double its width.The area , in square cm , of the rectangle is
(1) 30
(2) 50
(3) 100
(4) 25 ( CTET FEB 2014)
Answer: (2) 50
Solution:
Perimeter of square = 4 x a = 20
=> A = 5 cm
Since, width of the square is equal to the width of the rectangle = 5 cm
And the length of the rectangle is twice the width = 10 cm ( Given)
And therefore the area is 5x10 = 50 Square cm.
Q2. The internal length. breadth and height of a rectangular box A are 20 cm, 18 cm and 15 cm respectively and that of the box B are 18cm, 12cm and 5 cm respectively. The volume of the Box A is how many times that of Box B?
(1) 4
(2) 5
(3) 6
(4) 3 ( CTET FEB 2014)
Answer: (2) 5
Solution: Volume of Box A is 20x18x15 and Volume of Box B is 18x12x5
Therefore, the volume of Box A to that of Box B is = (20x18x15)/(18x12x5) = 5
Q3. Which of the following is not correct?
(1) Area of square of side 10 cm = area of rectangle of side 10 cm and 0.1m
(2) 1 m 5 cm = 1.5m
(3) 0.40 is same as 0.4
(4) Rupee 3/4 = Rupee 0.75
Answer: (2) 1.5m
Solution:
(1) 0.1 m = 10 cm and hence both are equal
(2) 5 cm = 0.05 m, hence 1 m 5 cm = 1.05 not 1.05 m. Hence this is false.
(1) True
(1) True
Q4. One orange costs five and half rupees and one kg apple costs Rs. 80. Then the cost of one and half dozen of oranges and one and one three-fourth kg of apples is
(1) 219
(2) 229
(3) 239
(4) 209 ( CTET FEB 2014)
Answer: (3) 239
Solution:
Cost of one apple = Rs 5.5 and cost of one and half dozen is (18) = 18 x 5.5 = 99
Cost of one kg apples is Rs 80 and therefore cost of one and three-fouth apples is 1 + 3/4 is (7/4)x80 = 140
And therefore total cost is 140 + 99 = 239
Q5. The product of the place values of 5 and 6 in 70560 is
(1) 300
(2) 3000
(3) 30000
(4) 30 ( CTET FEB 2014)
Answer: (3) 30000
Solution:
Place value of 5 in 70560 is 500
and the place value of 6 in 70560 is 60
Therefore the product is 60x500 = 30000
Q6. When 3010301 is divided by 43, the quotient is
(1) 70707
(2) 70007
(3) 7077
(4) 7007
Answer: (2)70007
Q7. What should be subtracted from the product 3001 x 101 to get 300311?
(1) 2790
(2) 2090
(3) 2970
(4) 270
Answer: (3) 2970
Solution:
3001x101 = 303101
And 303101 - 300311 = 2790
Q8. ( Smallest Common multiple of 36 and 60) /( Highest Common Factor of 18 and 45 is equal to
(1). 20
(2). 30
(3). 40
(4) 10
Answer: (1). 20
Solution:
Smallest Common Multiple of 36 and 60 is 180
And Highest Common Factor of 18 and 45 is 9
And 180/9 = 20.
Q. 9 ( 10 tens + 11 hundreds + 12 ones ) equals
(1) 1213
(2) 111012
(3) 101112
(4) 1212
Answer:(4) 1212
Solution:
10 tens = 10*10 = 100
11 hundreds = 11*100= 1100
And 12 ones = 12*1 = 12
Adding the above numbers to get 100+1100+12 = 1212
Q10. The number of factors of 42 is
(1) 7
(2) 8
(3) 9
(4) 6
Answer:(2) 8
Solution:
We can obtain 42 through
1x42 = 42
2x21 = 42
3x14 = 42
6x7 = 42
Therefore, number of factors are 8
Q11. When 3488 is divided by 12 and 2478 is divided by 11, the difference between the remainders in both the cases is
(1) 5
(2) 6
(3) 7
(4) 3
Answer:(1) 5
Solution:
When 3488 is divided by 12 we get 8 as the remainder
and when 2478 is divided by 11 we get 3 as the remainder
And the difference is 8-3 = 5
Q12. A train leaves station P at 8:18 a.m. and reaches the station Q at 10:28 pm on the same day. The time taken by the train to reach Q is
(1) 14 hours 10 minutes
(2) 14 hours 46 minutes
(3) 18 hours 46 minutes
(4) 13 hours 10 minutes
Answer:(1) 14 hours 10 minutes
Solution:
From 8:18 am to 12 'o' clock , the time is 3 hours 42 minutes.
and the time differences between 12 'o' clock to 10:28 pm is 10 hours and 28 minutes.
Adding both the times to get 14 hours and 10 minutes.
Q13. 14 L 280ml of orange juice and 18L 830ml of carrot juice were mixed together. This mixture was filled in 15 bottles each containing 1.5 L. How much mixture was left
(1) 11 L 105 ml
(2) 9 L 610 ml
(3) 11 L 605 ml
(4) 10 L 610 ml
Answer:(4) 10 L 610 ml
Solution:
Mixture in 15 bottles of 1.5 L each = 1.5x15 = 22 L 500 ml
And total mixture is 33 L 110 ml
And the mixture left is 10 L 610 ml.
Q14. `One fourth of the pizza was eaten by Renu. The rest was equally distributed among 12 children.What part of the pizza did each children get?
(1) 1/16
(2) 1/32
(3) 3/16
(4) 1/8
Answer: (1) 1/16
Solution:
Pizza left after Renu ate 1/4 of it is 3/4.
And 3/4 of the pizza was distributed to 12 children and therefore the pizza left is (3/4)/(12) = 3/48 = 1/ 16
Q15. The number of seconds in 6 hours equals the number of minutes in
(1) 4 days
(2) 10days
(3) 15 days
(4) 2 days
Answer: (3) 15 days
Solution:
Number of seconds in 6 hours = 6x60x60 = 21600 seconds
Now, to get the number of days that could come 21600 minutes, we divide 21600 by 60 to get 360 hours and divide 360 hours by 24 hours to get 15 days
Q16. Consider the following :
5 + 3 = ?
The open-ended question corresponding to the above close-ended question is
(1) Find the sum of 5 and 3.
(2) What shall be added to 5 to get 8.
(3) Give any two numbers whose sum is 8.
(4) What is the sum of 5 and 3?
Answer: (3) Give any two numbers whose sum is 8.
Explanation:
The above close-ended question fixes the numbers as 3,5 and 8 whereas option (3) can have 6,2 and 8 and 7,1 and 8 and more.
Q17. 'Tall shape of Mathematics' mentioned in the NCF, 2005 refers to
(1) solving challenging problems
(2) creating math games
(3) providing hands-on experience
(4) building of one concept on other
Answer:(4) building of one concept on other
Q18. 750 ml juice is filled in one bottle and six such bottles are packed in one carton. The number of cartons needed for 450 litres of juice is
(1) 75
(2) 80
(3) 90
(4) 100
Answer:(4) 100
Solution:
First we calculate the juice in 1 carton which is 750 x 6 = 4500 ml or 4.5 Litres
And to calculate the number of cartons required to pack 450 litres is 450/4.5 = 100 cartons
(1) 30
(2) 50
(3) 100
(4) 25 ( CTET FEB 2014)
Answer: (2) 50
Solution:
Perimeter of square = 4 x a = 20
=> A = 5 cm
Since, width of the square is equal to the width of the rectangle = 5 cm
And the length of the rectangle is twice the width = 10 cm ( Given)
And therefore the area is 5x10 = 50 Square cm.
Q2. The internal length. breadth and height of a rectangular box A are 20 cm, 18 cm and 15 cm respectively and that of the box B are 18cm, 12cm and 5 cm respectively. The volume of the Box A is how many times that of Box B?
(1) 4
(2) 5
(3) 6
(4) 3 ( CTET FEB 2014)
Answer: (2) 5
Solution: Volume of Box A is 20x18x15 and Volume of Box B is 18x12x5
Therefore, the volume of Box A to that of Box B is = (20x18x15)/(18x12x5) = 5
Q3. Which of the following is not correct?
(1) Area of square of side 10 cm = area of rectangle of side 10 cm and 0.1m
(2) 1 m 5 cm = 1.5m
(3) 0.40 is same as 0.4
(4) Rupee 3/4 = Rupee 0.75
Answer: (2) 1.5m
Solution:
(1) 0.1 m = 10 cm and hence both are equal
(2) 5 cm = 0.05 m, hence 1 m 5 cm = 1.05 not 1.05 m. Hence this is false.
(1) True
(1) True
Q4. One orange costs five and half rupees and one kg apple costs Rs. 80. Then the cost of one and half dozen of oranges and one and one three-fourth kg of apples is
(1) 219
(2) 229
(3) 239
(4) 209 ( CTET FEB 2014)
Answer: (3) 239
Solution:
Cost of one apple = Rs 5.5 and cost of one and half dozen is (18) = 18 x 5.5 = 99
Cost of one kg apples is Rs 80 and therefore cost of one and three-fouth apples is 1 + 3/4 is (7/4)x80 = 140
And therefore total cost is 140 + 99 = 239
Q5. The product of the place values of 5 and 6 in 70560 is
(1) 300
(2) 3000
(3) 30000
(4) 30 ( CTET FEB 2014)
Answer: (3) 30000
Solution:
Place value of 5 in 70560 is 500
and the place value of 6 in 70560 is 60
Therefore the product is 60x500 = 30000
Q6. When 3010301 is divided by 43, the quotient is
(1) 70707
(2) 70007
(3) 7077
(4) 7007
Answer: (2)70007
Q7. What should be subtracted from the product 3001 x 101 to get 300311?
(1) 2790
(2) 2090
(3) 2970
(4) 270
Answer: (3) 2970
Solution:
3001x101 = 303101
And 303101 - 300311 = 2790
Q8. ( Smallest Common multiple of 36 and 60) /( Highest Common Factor of 18 and 45 is equal to
(1). 20
(2). 30
(3). 40
(4) 10
Answer: (1). 20
Solution:
Smallest Common Multiple of 36 and 60 is 180
And Highest Common Factor of 18 and 45 is 9
And 180/9 = 20.
Q. 9 ( 10 tens + 11 hundreds + 12 ones ) equals
(1) 1213
(2) 111012
(3) 101112
(4) 1212
Answer:(4) 1212
Solution:
10 tens = 10*10 = 100
11 hundreds = 11*100= 1100
And 12 ones = 12*1 = 12
Adding the above numbers to get 100+1100+12 = 1212
Q10. The number of factors of 42 is
(1) 7
(2) 8
(3) 9
(4) 6
Answer:(2) 8
Solution:
We can obtain 42 through
1x42 = 42
2x21 = 42
3x14 = 42
6x7 = 42
Therefore, number of factors are 8
Q11. When 3488 is divided by 12 and 2478 is divided by 11, the difference between the remainders in both the cases is
(1) 5
(2) 6
(3) 7
(4) 3
Answer:(1) 5
Solution:
When 3488 is divided by 12 we get 8 as the remainder
and when 2478 is divided by 11 we get 3 as the remainder
And the difference is 8-3 = 5
Q12. A train leaves station P at 8:18 a.m. and reaches the station Q at 10:28 pm on the same day. The time taken by the train to reach Q is
(1) 14 hours 10 minutes
(2) 14 hours 46 minutes
(3) 18 hours 46 minutes
(4) 13 hours 10 minutes
Answer:(1) 14 hours 10 minutes
Solution:
From 8:18 am to 12 'o' clock , the time is 3 hours 42 minutes.
and the time differences between 12 'o' clock to 10:28 pm is 10 hours and 28 minutes.
Adding both the times to get 14 hours and 10 minutes.
Q13. 14 L 280ml of orange juice and 18L 830ml of carrot juice were mixed together. This mixture was filled in 15 bottles each containing 1.5 L. How much mixture was left
(1) 11 L 105 ml
(2) 9 L 610 ml
(3) 11 L 605 ml
(4) 10 L 610 ml
Answer:(4) 10 L 610 ml
Solution:
Mixture in 15 bottles of 1.5 L each = 1.5x15 = 22 L 500 ml
And total mixture is 33 L 110 ml
And the mixture left is 10 L 610 ml.
Q14. `One fourth of the pizza was eaten by Renu. The rest was equally distributed among 12 children.What part of the pizza did each children get?
(1) 1/16
(2) 1/32
(3) 3/16
(4) 1/8
Answer: (1) 1/16
Solution:
Pizza left after Renu ate 1/4 of it is 3/4.
And 3/4 of the pizza was distributed to 12 children and therefore the pizza left is (3/4)/(12) = 3/48 = 1/ 16
Q15. The number of seconds in 6 hours equals the number of minutes in
(1) 4 days
(2) 10days
(3) 15 days
(4) 2 days
Answer: (3) 15 days
Solution:
Number of seconds in 6 hours = 6x60x60 = 21600 seconds
Now, to get the number of days that could come 21600 minutes, we divide 21600 by 60 to get 360 hours and divide 360 hours by 24 hours to get 15 days
Q16. Consider the following :
5 + 3 = ?
The open-ended question corresponding to the above close-ended question is
(1) Find the sum of 5 and 3.
(2) What shall be added to 5 to get 8.
(3) Give any two numbers whose sum is 8.
(4) What is the sum of 5 and 3?
Answer: (3) Give any two numbers whose sum is 8.
Explanation:
The above close-ended question fixes the numbers as 3,5 and 8 whereas option (3) can have 6,2 and 8 and 7,1 and 8 and more.
Q17. 'Tall shape of Mathematics' mentioned in the NCF, 2005 refers to
(1) solving challenging problems
(2) creating math games
(3) providing hands-on experience
(4) building of one concept on other
Answer:(4) building of one concept on other
Q18. 750 ml juice is filled in one bottle and six such bottles are packed in one carton. The number of cartons needed for 450 litres of juice is
(1) 75
(2) 80
(3) 90
(4) 100
Answer:(4) 100
Solution:
First we calculate the juice in 1 carton which is 750 x 6 = 4500 ml or 4.5 Litres
And to calculate the number of cartons required to pack 450 litres is 450/4.5 = 100 cartons
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