CTET - 2015 Solved Math Questions Paper-1 September

Q31. Manipulative tools are important for learners at primary level as they help them most to:

       1.       Perform better in examination

       2.       Understand basic mathematical concepts

       3.       Solve word problems

       4.       Speed up mental and oral calculations

    Answer: (2) understanding basic mathematical concepts

    

Q32. Which one of the following questions is open ended?

       1.       Write any two numbers whose product is 45.

       2.       Use number line to find 3 times 15

       3.       Find 15 x 3

       4.       How will you multiply 15 by 3?

     

      Answer: (1)  Write any two numbers whose product is 45.

      Open ended questions are those that can more than one solution. Here the final answers for options 2,3,4 is 45 whereas only in option 1 we can have the 2 sets of two numbers whose product is (15,3),(9.5)

 

Q33. Some students of class II, face difficulty in the addition of two digit numbers involving  ‘carrying over’?

       1.       Understanding of difference between face value and place value

       2.       Understanding the importance of zero

       3.       Understanding of regrouping process

       4.       Interest in mathematics

   

      (3)  Understanding of regrouping process

Q34. Which one of the following is an important characteristic of good mathematics textbooks at primary level?

       1.       It should contain numerous exercises to give rigorous practice

       2.       It should be attractive and colourful

       3.       It must be thick and large

       4.       Concepts should be introduced through contexts

    Answer: Concepts should be introduced through contexts

Q35. According to ‘Van Hiele level of geometry’ students who can describe and sort out shapes on the basis of appearance are at:

      1.       Level 2 – Informal deduction

      2.       Level 3 – formal deduction

      3.       Level 0 – visualization

      4.       Level 1 – analysis

Answer:       3.       Level 0 – visualization

Q36. Communication in mathematics class refers to developing ability to :

      1.       Give prompt response to questions asked in class

      2.       Contradict the views of others on problems of mathematics

      3.       Organize, consolidate and express mathematical thinking

      4.       Interpret data by looking at bar graphs

Answer:      3.       Organize, consolidate and express mathematical thinking

Q37.  If a learner is able to perform the four basic operations on whole numbers, fractions and decimal numbers, the learner is at:

      1.       Factoring phase

      2.       Operating phase

      3.       Quantifying phase

      4.       Partitioning phase

Answer:      2.       Operating phase 

Q38 . National curriculum framework, 2005 recommends that teaching of mathematics at primary level should focus on:

      1.       Abstract concepts of mathematics.

      2.       Helping students to connect classroom learning with everyday life.

      3.       Helping students to acquire international standards in learning of mathematics

      4.       Preparation for higher mathematics

    Answer:       2.       Helping students to connect classroom learning with everyday life.

 

Q39. Which one of the following is not an important aspect of number-sense?

      1.       Counting

      2.       Writing numbers

      3.        Conservation

      4.       Seriation

Answer:       2.       Writing numbers

Q40. A teacher gives 36 tiles to students of class IV and asks them to arrange them in all possible rectangles. Which one of the following concept cannot be addressed by using this activity?

      1.       Area

      2.       Volume

      3.       Factors

      4.       Multiplication

Answer:       2.       Volume

Q41. Ten thousands + ten hundreds + ten tens is equal to :

      1.       11100

      2.       11010

      3.       101010

      4.       11110

   

  Answer:  Ten thousands + ten hundreds + ten tens  = 10 x 1000 + 10 x100 + 10x10 = 10000 + 1000 + 100 =    11100

Q42. The sum of remainders obtained on dividing 12112 by 11 and 13223 by 13 is :

     1.       4

     2.       5

     3.       2

     4.       3

  

   Answer:      4.       3

                   Remainder of (12112/11) = 1 

                   Remainder of (13223/13)= 2

s  Therefore sum of the remainders = 3

    

Q43. The difference between the place value of 6 and the face value of 4 in 56431 is

     1.       5600

     2.       5996

     3.       2

     4.       999

     Answer:      2.       5996 

      Place value of 6 in 56431 is 6000 and the face value of 4 in 56431 is 4.

      And the difference is   6000 - 4 = 5696 . 

      To know more about face value and place value read difference-between-face-value-and-place

  

Q44. The product of the smallest common multiple and the biggest common multiple factor of 30, 36 and 42 is:

     1.       7660

     2.       7650

     3.       7560

     4.       7460

   

     Answer:      3.       7560

            30 =  2 x 3 x 5 

            36 = 2 x 2 x 3 x 3 

            42 = 2 x 3 x 7

           Therefore LCM = 1260 and HCF= 6  and their product = 7560

          

Q45. The sum of all the positive factors of 84 which are multiplies of 7 , is:

     1.       189

     2.       196

     3.       112 

     4.       113

      Answer:       2.       196

     84 = 7 x 2  x 2 x 3

     Factors of 84 are 1,2,3,7,14,21,28,42,84 and out of these the factors that are multiples of 7 are  7,14,21,28,42,84 = 196

Q46. When it is 8:49 pm, in Delhi, it is 1:19 a.m. on the next day in Sydney when it is 11:19 a.m. in Delhi?

     1.       3:49

     2.       6:29

     3.       6:49

     4.       3:19

    Answer:      3.       6:49

      The time difference between Sydney and delhi is 4 hours and 30 minutes from the data given. Now when it is  11:19 in Delhi then it is 3:49 p.m. in delhi.

Q47. On a map, half a centimeter shows 125 km on the ground. If two cities are actually 2000 kms apart on the ground , then the distance between them on the map is:

     1.       8 cm

     2.       10 cm

     3.       4 cm

     4.       6 cm

    Answer: 1.  8 cm.

     half a centimeter  represents 125 km. This  means 1 cm represents 250 km.

    Using unitary method,
           1 km is represented by (1/250) km
   and  2000 km is represented by (1/250)2000 = 8 cm
    To learn more about unitary method read Unitary Method

Q48. Which one of the following is not correct?

     1.       0.57 is the same as 0.5700

     2.       Area of a square of side 30 cm is the same as the area of a rectangle 4.5 m x 0.2 m

     3.       2009 millimeters = 2 litres 9 millimeters

     4.       25 hundredths = 25/100

    Answer:        2.       Area of a square of side 30 cm is the same as the area of a rectangle 4.5 m x 0.2 m
    
    Area of square of side 30 cm or 0.30 m  = 0.3 x 0.3 = 0.09 square meter
    and area of rectangle with sides 45 m x 0.2 meter = 0.9 square meter. and therefore different. 

Q49. There are 660 students in a school. Two-thirds of them are boys. Three fourths of the numbers of boys are players and one-fourth of the girls are players. Total number of players in the school is:

     1.       385

     2.       395

     3.       330

     4.       370
    Answer:     1.       385
    Number of boys = 2/3(660) = 440 and three fourth of 440 are players which means (3/4)440 = 330 boys are players.
.      Number of girls = 660 - 440 = 220 and one fourth are players = (1/4)220 = 55 girls 
     And total players = 330 + 55 = 385

Q50. Renu want to lay tiles on the floor of her house which is 9 m long and 7 m wide. Among the following sizes of tiles, which one should she buy so that the floor is tiled without cutting any tiles?

     1.       55 cm x 40 cm

     2.       35 cmx 45 cm

     3.       35 cm x 35 cm

     4.       40 cm x 65 cm

     Answer:      2.       35 cmx 45 cm
    The total area of the floor = 63 meters
    Only the option  2        35 cmx 45 cm = 0.1575 m completes divides 63. and therefore is the right answer.

   Q51. Number of seconds in 6 hours is equal to the number of minutes in:

     1.       15 days

     2.       16 days

     3.       10 days

     4.       12 days

   Answer:      1.       15 days
    Number of seconds in   hours = 6 x 60 x 60 seconds = 21600 seconds
    now number of minutes in 15 days = 15 x 24 x 60 = 21600 minutes and hence is the answer.
    

Q52. There are four cuboidal boxes with dimensions (in cm ) as given below:

Length   breadth  height

     1.                   20           25            18

     2.                   23           20            20

     3.                  20            22             21

     4.                   24           20             19

  Using which boxes can 18440 wooden centimeters cubes can be packed?

     1.       (ii) & (iii)

     2.       (ii) & (iv)

     3.       (i) & (ii)

     4.       (i) & (iii)

    Answer:      1.       (ii) & (iii)
    volume box 1 =  9000
    volume box 2 = 9200
    volume box 3 = 9240
    volume box 4 =  9120
    It is evident that adding box 2 and 3 will get 18440.

Q53. The length of a rectangle is two times that of a square whose perimeter is 80 cm. if breadth of the rectangle is 20 cm, and then the area (in cm²) of the rectangle exceeds the area of the square by:

     1.       300

     2.       400

     3.       100

     4.       150
     Answer:
     Perimeter of square = 80
     4 L = 80
        L = 20 cm
     area of square = 20 x 20 = 400 sq. cm
       Given that the length of the rectangle is two times the length of the square that means the length of the rectangle = 2 x 20 = 40 cm
     and the breadth of the rectangle given as 20 cm
     Therefore area of the rectangle  = (L x B) = (40 x 20) = 800 sq. cm
And the difference = 800 - 400 = 400 sq. cm

Q54. Haroon went to a fruit shop. He bought one and half dozen bananas at the rate of 2.5 per banana , three and a half kilogram apples at 57.60 per kg, one and half kg of mangoes at 75.40 per kg and 750 grams of grapes at 120 per kg . if he gave a note of 500 to the fruitseller , he will get back:

     1.       14.95

     2.       50.30

     3.       28.10

     4.       24.85
    Answer :  2.       50.30
    total expenditure =2.5 x 18 + 57.60 x 3.5 + 1.5 x 75.40 + 0.75x120 = 449.70  and the amount he would receive after deducting 253 from 500 is 50.30

Q55. 10290 books are to be packed in wooden boxes. If 98 books can be packed in one box and the cost of one box is 518 then the cost of boxes needed for this purposes is:

     1.       54,292

     2.       54,908

     3.       53,872

     4.       54,390

     Answer:
     number of boxes required = 10290/98 = 105
     and the cost of these 105 boxes is 105 x 518= 54390
 

Q56. Which of the following is the best sequence to teach the topic ‘ measurement of Length’ at primary stage?

     1.       Comparison -> using non-standard measures -> using standard measures -> developing standard unit

     2.       Developing standard unit -> using standard measure -> using non-standard measures - >  comparison

     3.       Using standard measures -> using non-standard measures -> developing standard unit - > comparison

     4.       Comparison -> using non-standard measures -> developing standard unit - > using standard measures

  Answer :  1.       Comparison -> using non-standard measures -> using standard measures -> developing standard unit

Q57. Learning objective for fourth grade students is given as:

“Students are able to order and compare two decimal numbers upto two decimals places”

This learning objective refers to:

1.       Disposition goal

2.       Social goal

3.       Content goal

4.       Process goal

 
Answer: 

3.       Content goal

Q58 which one of the following manipulative tools is required to develop geometrical concepts of  ‘symmetry ‘ and ‘reflection’ in class IV?

     1.       Dot paper

     2.       Abacus

     3.       Two sided counter

     4.       Beads string
 
   Answer:       1.       Dot paper

Q59 .  a debate was conducted in mathematics period of class V on “zero is the most powerful number”.

 This activity encourages the child to:

     1.       Write numbers containing zeros

     2.       Solve problems containing numbers

     3.       Collaborate with friends

     4.       Analyse and communicate

   Answer:      4.       Analyse and communicate 

60.  If a learner is having problem with numbers and calculations she/he may be having disability know as:

     1.       dyscalculia

     2.       visual – spatial organization

     3.       dyslexia 

     4.       dysgraphia 

Answer:      1.       dyscalculia