Geometric progression series is the one in which Tn+1
term is obtained by multiplying a fix quantity to Tn, known as common ratio.
A sample Geometric progression is a, ar, ar^2, ar^3, ar^4, ar^5…
Important Result:
For a GM the ratio Tn+1/Tn = r is always constant. This constant r is known as common ratio.
The sum of the GM series is
Sum = a(r^n-1)/((r-1) )
Where
A is the first term of the GM
r is the common ratio
n is the number of terms
Sum of the GM in terms of the last term and first term
Sum of GM = (r (last term) – first term)/((r-1))
Tn = Sn – Sn-1
Where,
Tn is the nth term of the GM
Sn is the sum of first nth terms of the GM
Sn+1 is the sum of first (n-1)th terms of the GM
If r, the common ratio of the GM is less than 1 then the sum of the GM for infinite terms is
Sum = a/(1-r)
Geometric Mean
The geometric mean of two numbers a and b is √ab
The geometric mean of n numbers a1, a2, a3, a4, a5, a6, a7, a8, a9,….an is
√(a1 a2 a3 a4 a5 a6 a7 a8 a9….an)
Inserting ‘n’ numbers of geometric means between any two numbers, A and B.
Let the two numbers between which the ‘n’ Geometric means are to inserted to be A and B.
Now there are (n+2) terms in the series. The first one is A and the last one is B.
Let assume the common ratio is r, then the last term B could be written as
B = A.r(n+1)
r(n+1) = B/A
r = (B/A)1/(n+1)
Therefore If we are given the value of A and B and the number of terms ‘n’ then we can easily insert n geometric means between A and B.
A sample Geometric progression is a, ar, ar^2, ar^3, ar^4, ar^5…
Important Result:
For a GM the ratio Tn+1/Tn = r is always constant. This constant r is known as common ratio.
The sum of the GM series is
Sum = a(r^n-1)/((r-1) )
Where
A is the first term of the GM
r is the common ratio
n is the number of terms
Sum of the GM in terms of the last term and first term
Sum of GM = (r (last term) – first term)/((r-1))
Tn = Sn – Sn-1
Where,
Tn is the nth term of the GM
Sn is the sum of first nth terms of the GM
Sn+1 is the sum of first (n-1)th terms of the GM
If r, the common ratio of the GM is less than 1 then the sum of the GM for infinite terms is
Sum = a/(1-r)
Geometric Mean
The geometric mean of two numbers a and b is √ab
The geometric mean of n numbers a1, a2, a3, a4, a5, a6, a7, a8, a9,….an is
√(a1 a2 a3 a4 a5 a6 a7 a8 a9….an)
Inserting ‘n’ numbers of geometric means between any two numbers, A and B.
Let the two numbers between which the ‘n’ Geometric means are to inserted to be A and B.
Now there are (n+2) terms in the series. The first one is A and the last one is B.
Let assume the common ratio is r, then the last term B could be written as
B = A.r(n+1)
r(n+1) = B/A
r = (B/A)1/(n+1)
Therefore If we are given the value of A and B and the number of terms ‘n’ then we can easily insert n geometric means between A and B.
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